Physics Problem , Need Help Quickly.

Student

Me prashneth hadana hati kiyala denna Puluwanda ??

1 ) Lamayek widuru bolayak 3.2m usaka sita bimata bamai. Eya bima wadi polapanina prawegaya , bima wadina prawegayen 3/4 k nam , widuru bolaya nagina usa kiyada ??
Bolaya palamuwara bima gatuna mohethe sita dewanawara bima gatena mohatha dakwa gatha wana kalaya kiyada ??

yasas

g=10ms^-2
පහලට
v²=u² + 2as
v²=0 + 2*10*3.2
v²=64
v=8ms^-1 බිම වදින ප්‍ර.
පොලා පනින ප්‍ර = 8*3/4 =6ms^-1 ඉහලට

ඉහලට
v²=u² + 2as
0=6² -2*10*s
s=36/20
s=1.8m බෝලය නගින උස

~O)
ඉහලට

s=ut+(1/2)at²
0=6t - (1/2)10t²
0=6 - 5t   {t අසමානයි 0}
t=6/5 s
t=1.2s

~O) ~O)

Student

@Yasas - Thank U Very Much !!