me gana hadala denna.
Sin A - Sin(B-C) = 2 CosB SinC
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A+B+C=pi lesa ganna wenawa. A,B,C thrikonayaka koona wenna one.
L.H.S= 2.cos{[A+B-C]/2}.sin{[A-(B-C)]} = 2.cos{[(pi-C)-C]/2}.sin{[(pi-B)-B]/2} = 2.cos(pi/2 -C).sin(pi/2 -B) = 2.sinC.cosB = R.H.S
mekath balanna
http://online-educator.blogspot.com/2014/04/vii.html
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